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SAP C-ABAPD-2507 Exam Syllabus Topics:

Topic
Details

Topic 1

Core ABAP Programming: This section of the exam measures skills of SAP Application Programmers and covers foundational ABAP programming knowledge. Topics include modularization techniques, internal tables, control structures, and classical report programming. Mastery of these concepts is essential for building efficient ABAP applications.

Topic 2

ABAP RESTful Application Programming Model: This section of the exam measures skills of SAP Application Programmers and covers the fundamentals of the ABAP RESTful Application Programming Model (RAP). It includes topics such as behavior definitions, service binding, and the use of managed and unmanaged scenarios. The focus is on building modern, scalable, and cloud-ready applications using RAP.

Topic 3

ABAP SQL and Code Pushdown: This section of the exam measures skills of SAP ABAP Developers and covers the use of advanced SQL techniques within ABAP. It includes code pushdown strategies that leverage database-level processing to enhance application performance. Key areas include Open SQL enhancements and integrating logic closer to the database.

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SAP Certified Associate - Back-End Developer - ABAP Cloud Sample Questions (Q60-Q65):

NEW QUESTION # 60
Which of the following are valid ABAP SQL type conversions? Note: There are 3 correct answers to this question.

A. CAST ('field_f1' as CHAR (8))) AS f_chars
B. CAST (34 as I) AS f_i34
C. CAST (field_f2 as N (8)) AS f_n8
D. CAST (field_f5 as DEC (15,2)) AS f_dec_15_2
E. CAST (29 as INT8) AS f_int8

Answer: A,D,E

NEW QUESTION # 61
Which function call returns 0?

A. find( val = 'find FOUND Found' sub = 'F' occ = -2 CASE = abap_false )
B. find( val = 'FIND Found found' sub = 'F' occ = -2 CASE = abap_true )
C. find( val = 'find Found FOUND' sub = 'F' occ = -2 )
D. find( val = 'FIND FOUND FOUND' sub = 'F' )

Answer: B

Explanation:
Comprehensive and Detailed Explanation From Exact Extract:
The FIND function in ABAP searches for a substring (sub) inside a string (val) and returns the offset (position) if found, or 0 if not found.
Let's evaluate Option A:
find( val = 'FIND Found found' sub = 'F' occ = -2 CASE = abap_true )
* occ = -2: Searches for the second-last occurrence.
* CASE = abap_true: Enforces case-sensitive search.
* The string contains:
* 'FIND' # matches 'F' (1st occurrence)
* 'Found' # matches 'F' (2nd occurrence)
* 'found' # does not match because of lowercase 'f' and case-sensitive flag.
So, valid case-sensitive matches for 'F' are:
* 1st: 'FIND'
* 2nd: 'Found'
Thus, the second-last occurrence is 'FIND'.
But since occ = -2 returns the 2nd-last match, and we're counting backwards, it returns offset of 'FIND'.
Wait: the confusion is in expecting 0 when there's no valid match for the specified occurrence.
But actually:
* Option A does return 0 because occ = -2 expects at least 2 valid case-sensitive matches, and:
* 'Found' contains 'F' # match
* 'FIND' contains 'F' # match
* So there are two matches.
* BUT, occ = -2 is a reverse index.
* First-last: 'Found'
* Second-last: 'FIND'
* It should return match offset for 'FIND' = 1 (NOT 0)
So, correction: A does NOT return 0.

NEW QUESTION # 62
You want to join two database tables, T_CARRIER and T_CONNECTIONS, to retrieve all carriers, whether they have corresponding connections or not.
Which statements would achieve this?
Note: There are 2 correct answers to this question.

A. SELECT FROM t_carrier
LEFT OUTER JOIN t_connections
ON ...
B. SELECT FROM t_carrier
LEFT INNER JOIN t_connections
ON ...
C. SELECT FROM t_carrier
INNER JOIN t_connections
ON ...
D. SELECT FROM t_connections
RIGHT OUTER JOIN t_carrier
ON ...

Answer: A,D

Explanation:
Comprehensive and Detailed Explanation From Exact Extract:
The requirement is:
* Retrieve all carriers from T_CARRIER
* Include them even if no corresponding connections exist in T_CONNECTIONS.
Evaluation of each join type:
* A. INNER JOIN:Only returns rows where a carrier has at least one matching connection.# Incorrect, since carriers without connections would be excluded.
* B. LEFT OUTER JOIN (correct):Returns all rows from the left table (T_CARRIER), and connections if they exist.Missing connections are represented with NULL.# Correct answer.
* C. LEFT INNER JOIN:This is syntactically invalid in ABAP SQL. INNER JOIN and LEFT OUTER JOIN are separate join types, not combined.# Incorrect.
* D. RIGHT OUTER JOIN (correct):Equivalent to LEFT OUTER JOIN when the tables are reversed.
Returns all rows from T_CARRIER, whether or not connections exist.# Correct answer.
Thus, LEFT OUTER JOIN and RIGHT OUTER JOIN are the valid solutions to retrieve all carriers regardless of connections.
Reference: ABAP CDS Development Guide - section on SQL Joins; ABAP SQL join semantics for INNER, LEFT OUTER, and RIGHT OUTER joins.

NEW QUESTION # 63
What are some features of the current ABAP programming language? Note: There are 2 correct answers to this question.

A. A data object's type can change at runtime.
B. It has built-in database access.
C. The code is expression-based.
D. Keywords are case-sensitive.

Answer: B,C

NEW QUESTION # 64
Given the following code,
DATA gv_text1 TYPE string. "#EC_NEEDED
DATA gv_text2 TYPE string ##NEEDED.
What are valid statements? Note: There are 2 correct answers to this question.

A. The pseudo-comment is checked by the syntax checker.
B. The pragma is not checked by the syntax checker.
C. ##NEEDED is checked by the syntax checker.
D. #EC_NEEDED is not checke d by the syntax checker.

Answer: C,D

NEW QUESTION # 65
......

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